# Calculus

Consider the following.
cos(x) + sqrt(y)= 1

(a) Find y' by implicit differentiation.

(b) Solve the equation explicitly for y and differentiate to get y' in terms of x.
y' = ?

(c) Check that your solutions to parts (a) and (b) are consistent by substituting the expression for y into your solution for part (a).
y' =?

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1. I hope for a) you had
-sinx + (1/2)y^(-1/2) dy/dx = 0
dy/dx = 2√y sinx

b) from the original:
√y = 1 - cosx
square both sides
y = 1 - 2cosx + cos^2 x
dy/dx = 2sinx + 2cosx(-sinx)
= 2sinx(1 - cosx) , but 1-cosx = √y
= 2sinx √y , which matches my other dy/dx

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