Please help me with this math problem: divide (20x^2-12x+8)/(2x+8)
these are the choices:
A. 10x-34+ 280/2x-8
B. 10x+34+ 280/2x-8
C. 10x+46+ 376/2x-8
D. 10x-46+ 376/2x+8
Thanks so much.
done, see your later post
To divide the polynomial (20x^2-12x+8) by (2x+8), you can use the process of polynomial long division.
First, divide the first term of the numerator (20x^2) by the first term of the denominator (2x). This gives you 10x as the first term of the quotient.
Next, multiply the entire denominator (2x+8) by the 10x from the previous step. This gives you 20x^2+80x.
Subtract this result (20x^2+80x) from the numerator (20x^2-12x+8).
(20x^2-12x+8) - (20x^2+80x) = -92x+8
Now, bring down the next term from the numerator (-92x) and divide it by the first term of the denominator (2x). The result is -46.
Multiply the entire denominator (2x+8) by -46. This gives you -92x-368.
Subtract this result (-92x-368) from the previous result (-92x+8).
(-92x+8) - (-92x-368) = 376
At this point, there are no more terms left in the numerator. The quotient is 10x - 46, and the remainder is 376.
So the correct answer is D. 10x-46+ 376/(2x+8).