Calculus
- 👍
- 👎
- 👁
-
- 👍
- 👎
-
- 👍
- 👎
Respond to this Question
Similar Questions
-
Calculus
a particle starts at time t = 0 and moves along the x axis so that its position at any time t>= 0 is given by x(t) = ((t-1)^3)(2t-3) a.find the velocity of the particle at any time t>= 0 b. for what values of t is the velocity of
-
Calculus
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 – 21t^2 + 60t + 3 for t ≥ 0. Find the position and acceleration of the particle at the instant the when the particle reverses direction. Include
-
calculus
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''(t) is its acceleration. A particle moves along the x-axis at a velocity of v(t) = 5/√t, t > 0. At
-
math
a particle starts at time t = 0 and moves along the x - axis so that its position at any time t is greater than or equal to zero is given x(t) = (t-1)^3(2t-3) A. Find the velocity of the particle at any time t greater than or
-
Calculus
1) A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t) = (t)In(2t). Find the acceleration of the particle when the velocity is first zero. 2) The driver of a car traveling at 50 ft/sec suddenly
-
Calculus
Given the position function, s(t)= (-t^3/3)+(13t^2 /2)-30t, between t=0 and t = 9, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right. a) 3 < t < 9 b) 5 <
-
AP CALC. AB
1.The position of a particle moving on the line y = 2 is given by x(t)= 2t^3-13t^2+22t-5 where t is time in seconds. When is the particle at rest? a. t =0.268, 2.500, and 3.732 b. t = 0, 1.153, and 3.180 c. t = 1.153, 2.167 and
-
calculus
5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is
-
calculus
A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 5t + 3, s(0) = 0, s(1) = 20 s(t) =
-
math
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'' (t) is its acceleration. x(t) = t3 − 12t2 + 21t − 9, 0 ≤ t ≤ 10 Find the open t-intervals on
-
HS Calculus
Having trouble with this questions. Please help. A particle moves on the x-axis so that its position at any time t (is greater than or equal to) 0 is given by x(t) = 2te^-t a) Find the acceleration of the particle at t=0 b)find
-
CALCULUS BC
a particle moves on the x-axis in such a way that its position at time t is given by x(t)=3t^5-25^3+60t. for what values of t is the particle moving to the left. a.-2
You can view more similar questions or ask a new question.