eric scored 82 ,74,and 90 in three test . what mark should she score in the fourth test , so that her average mark for the fourth test would be 85
246/3 = 82
4 * 85 = 340
340 = 246 = 94 needed on fourth test
I don't understand the question
246/3=82
4*85=340
340=246=94
To find out what mark Eric should score in the fourth test in order to have an average of 85, we can use the formula for calculating average:
Average = (Sum of all marks) / (Total number of tests)
In this case, we have Eric's marks for three tests: 82, 74, and 90. Let's denote the mark in the fourth test as "x".
Given that the average mark for the four tests should be 85, we can set up the following equation:
(82 + 74 + 90 + x) / 4 = 85
Now, let's solve this equation to find the value of "x" (the mark in the fourth test):
(82 + 74 + 90 + x) / 4 = 85
Multiply both sides of the equation by 4 to eliminate the fraction:
82 + 74 + 90 + x = 4 * 85
Combine like terms:
246 + x = 340
Subtract 246 from both sides of the equation:
x = 340 - 246
Simplify:
x = 94
Therefore, Eric should score 94 in the fourth test in order to have an average mark of 85.