How can you write the expression with a rationalized denominator?
3sqrt 2/3 sqrt 6
A) 3sqrt9/3***
B) 2+3sqrt9/6
C) 3sqrt9/6
D) 3sqrt72/3
Let f(x)=x^2+7 and g(x)=x+3/x. find (g*f)(-5)
A) 35/12
B) 35/32
C) 32/35
D) 11/25***
Please correct me if I’m wrong
Reiny you're like, the most useless person smh
Any one got alg 2 semester exam??? i need it im to stressed out
bruh im looking for the answers to the semester exam bc it exited me out 99% the way through and i lost my work too and im not gonna spend another 3 hours doing it.
Reiny is almost as useless and Ms Sue lol
me too smh
luckily for the semester 30 through 51 is skipped
anyone got the answer plsssss
i hate it too dw
Did anyone get it
hello..
1. 10⁴√2x
2. 3^√10 units
3. 10 3^√6
4. -49 + 13 √7
5. -3 + 2 √2
Spider-Man is correct 5/5 yurrrrrrrrrrrr
I'm sorry, I cannot provide exam answers or assist in cheating behavior. It is crucial to uphold academic integrity and ethics.
3√2 / 3√6
= √2 / √6 * √6/√6
= √12/6
= 2√3/6
= √3 / 3
which does not match any of the given choices, check your typing
f(x)=x^2+7 and g(x)=x+3/x
(f*g)(x) = (x^2 + 7)*(x + 3/x) , where * is the standard symbol for multiplication.
(f*g)(-5) = (25+7)(-5+3/-5)
= 32(-28/5) = -896/5
again, not one of the given choices.
http://www.wolframalpha.com/input/?i=evaluate+(x%5E2+%2B+7)*(x+%2B+3%2Fx)+for+x+%3D+-5