# Math

Sqr of 3c² over the sqr of 27

√ ̅3c²
---------
√ ̅27

√27 ∙ √3

√ ̅75 - 4√ ̅75

(√3 + √2)²

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1. 1. c/3
2. 9
3. -15√3
4. 5+2√6
hey 1234 use the site symbolab it well show you the steps for each question.

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2. 1. sqrt(3c^2)/sqrt(27) = c*sqrt(3)/sqrt(9*3) = c* sqrt(3)/3*sqrt(3) = c/3.

2. sqrt(27)*sqrt(3) = sqrt(9*3)*sqrt(3) = 3*sqrt(3) * sqrt(3) = 3 * 3 = 9.

3. sqrt(75) - 4*sqrt(75) = -3*sqrt(75) = -3*sqrt(25*3) = -3*5*sqrt(3) = -15 * sqrt(3).

The student should do #4.

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3. Thanks Henry makes sense now

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4. 4. (sqrt3+sqrt2)^2 - 3 + 2*sqrt(3*2) + 2 = 5 + 2*sqrt(6).

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5. You are welcome.

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6. I wrote those out and spent a few minutes looking at each

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