Can you pleas Solve the quadric equation step by step
4x square =13x+2
4x^2 = 13x + 2
subtract 13x and 2 from both sides
4x^2 - 13x - 2 = 0
Now use the quadratic formula, since it does not factor.
x2^-x+1=0
i don't see the answer and the steps
To solve the quadratic equation 4x^2 - 13x - 2 = 0, we will use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Here, a = 4, b = -13, and c = -2.
Substituting these values into the quadratic formula, we get:
x = (-(-13) ± √((-13)^2 - 4(4)(-2))) / (2(4))
Simplifying further:
x = (13 ± √(169 + 32)) / 8
x = (13 ± √(201)) / 8
Now, let's evaluate the expression for both cases of the ± symbol.
Case 1:
x = (13 + √(201)) / 8
Case 2:
x = (13 - √(201)) / 8
These are the two possible solutions to the quadratic equation.