Math

A person leaves her home and walks 6 miles due east and then 4 miles southeast?How far away from home is she?What is her net displacement(determine the magnitude and direction of the displacement vector)?

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  1. east ... 6 + 2√2

    south ... 2√2

    use Pythagoras to find the distance

    the direction angle is in Quad IV ... tan(Θ) = south / east

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  2. D^2 = 6^2 + 4^2 = 52
    D = 2√13 or appr 7.2 units from home

    angle:
    as Scott said, tanØ = 4/6
    Ø = appr 33.7°
    depending on your notation, direction angle = -33.7°
    or bearing of 123.7°
    or E 33.7° S

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