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Calculus

f is a differentiable function on the interval [0, 1] and g(x) = f(2x). The table below gives values of f '(x). What is the value of g '(0.1)
x| .1 .2 .3 .4 .5
f'(x)| 1 2 3 -4 5

So I know f(x) would be the integral of f'(x) which you can get with a Riemann sum, right? But then what do you do when you get that?

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Anonymous

  1. g(x)=f(2x)
    g'(x)=f'(2x)*2

    It's just the chain rule

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    Steve

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