# math;)

The equation 2sinx+sqrt(3)cotx=sinx is partially solved below.

2sinx+sqrt(3)cotx=sinx
sinx(2sinx+sqrt(3)cotx)=sinx(sinx)
2sin^2x+sqrt(3)cosx=sin^2x
sin^2x+sqrt(3)cosx=0

Which of the following steps could be included in the completed solution?
a. cos^2x-sqrt(3)cosx-1=0
b. sin^2x-sqrt(3)sinx-1=0
c. (1-cos^2x)(sqrt(3)cosx)=0
d. (1-sin^2x)(sqrt(3)sinx)=0

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1. looks like A to me
Then everything is in terms of cosx

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2. No Steve is actually correct, A, or cos^2x - sqrt3 cos x - 1 = 0 is correct

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3. 1. A [ cos^2 (x) - sqrt(3)*cos(x) - 1 = 0 ]
2. B [ f(x) = sqrt(sin x) ]
3. D [ 7.6 hours ]
100% ur welcome

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