a bag contains 7 green marbles, 9 red marbles, 10 orange marbles, 5 brown marbles, and 10 blue marbles. you choose a marble, replace it and choose again. what is P(red, then blue)?

A. 77/164
B. 19/41
C. 90/1681
D. 45/41

Im kinda confused but i think its B

9/41 * 10/41 = 90/1681

To find the probability of selecting a red marble and then a blue marble, we need to calculate the individual probabilities and multiply them together.

First, let's find the probability of selecting a red marble. There are a total of 41 marbles in the bag (7 green + 9 red + 10 orange + 5 brown + 10 blue). Since you replace the marble after selecting, the probability of selecting a red marble on the first draw is 9/41.

Next, let's find the probability of selecting a blue marble on the second draw. Again, there are 41 marbles in the bag, so the probability of selecting a blue marble on the second draw is also 10/41.

To find the probability of selecting a red marble and then a blue marble, we multiply these two probabilities together: (9/41) * (10/41) = 90/1681.

So the correct answer is C. 90/1681.