# algebra

The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right.
Find the GCF:
16x^2z ,40xz^2 , 72z^3
= 3^3z

Factor our GCF:
a(a+1) - 3(a+1)
= a+1

Factor Polynomial:
9a^2 - 64b^2
= (3a+8b)(3a-8b)

9w - w^3
= w(3) (?really unsure if correct?)

I'm not sure how to do the following, or where to even begin. Some help getting started would be very appreciated! :)

Factor Polynomials:
x^3y + 2x^2y^2 + xy^3

x^3 + ax + 3a + 3x^2

Factor:
18z + 45 +z^2

asked by kay bri
1. 16x^2z ,40xz^2 , 72z^3
the GCF I see is 4xz, I can't see how you got your answer.

a(a+1) - 3(a+1)
= (a+1)(a-3) fully factored

9a^2 - 64b^2
= (3a+8b)(3a-8b) that is ok

9w - w^3 , I see a common factor of 3w
= 3w(3 - w^2)

x^3y + 2x^2y^2 + xy^3 first go for a common factor
= xy(x^2 + 2xy + y^2)
= xy(x+y)(x+y)
= xy(x+y)^2

x^3 + ax + 3a + 3x^2
this is a "grouping" type of factoring
= x^3 + 3x^2 + ax + 3a
= x^2(x+3) + a(x+3)
= (x+3)(a+3)

18z + 45 +z^2
= z^2 + 18z + 45
= (z+15)(z+3)

posted by Reiny
2. in the first one: 16x^2z ,40xz^2 , 72z^3
the only question I have is, how can it be 4xz when they don't all have the variable 'x'? the way I factored it was like this:
16x^2z
16 = 8 & 2 x^2z
4&2 (x)(x)(z)
2&2
= 2^4

40xz^2
40 = 10 & 4 xz^2
5&2 2&2 (x)(z)(z)
= 5(2^3)

72z^3
72 = 36 & 2 z^3
18&2 (z)(z)(z)
9&2
3&3
= 3^2(2^3)

with the answer being 2^3z, which is what they all have in common

posted by kay bri
3. 3w-3

posted by Anonymous

## Similar Questions

1. ### Algebra

The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right. Find the GCF: 16x^2z ,40xz^2 , 72z^3 = 3^3z Factor our GCF: a(a+1) - 3(a+1) = a+1 Factor Polynomial:
2. ### algebra 2

Solve the following systems of equations. If the system cannot be solved ,state that it cannot be solved and explain why. 1.3x+y=7 3x+y=10 2. 5x-2y=-24 -4y=-48-10x
3. ### math(galerkin,collocation)

can some one plz help how to make trial function for solving equations in collocation and galerkin methods which satisfy the given boundary conditions. example y"+y=3*square(x) with y(0)=0 and y(2)=3.5. is there some method of
4. ### Math..

4(x+1/2)-2(x+3/2) less than. Or equal to 5 ( i. Solved it im just checking my answers to be sure )
5. ### English

1. I can make a vegetable soup. 2. I can make vegetable soup. (Do we have to use 'a' ornot?) 3. I can make ramen. 4. I can make pasta. 5. I can make seafood. 6. I can make raw fish. 7. I can make noodles. 8. I can make sandwich.
6. ### Vectors - Reiny

Thank you for the help! "When I solved equations 2 and 3 I got u=0 and t=-1, giving me r = (-2,-3,0) in both r = ... equations." Ok I'll check that. I just have a question...how would you get r = (-2,-3,0) when u = 0 and t = -1?
7. ### Math

Can you Check my work please? Let N(t) be the number of bacteria after t days. Then N(t) = Pa^t for some constants P and a. Measurements indicate that N(4) = 5600 and N(8) = 362, 000. b. Write down two equations for P and a, one
8. ### math

pls help me to solved this equation 1. 6y=x+18 2y-x=6, 2. 4x=3y=13 2x-4y=1 3. y=3x-12 2/3x=2/3-1/6y pls help me now. this equation is Systems of Linear Equations Solved Algebraically.
9. ### To Helper

I had a problem to solve, and I don't get how to make equations from this problem. Mrs. Chans math class contributed 2 dollars and \$1 coins to an earthquake relief fund. the number of \$1 coins contributed was 8 less than 5 times
10. ### Algebra

Find all solutions to the following system of equations: x + 3y + 2z = 6 -3x + y + 5z = 29 -2x - 3y + z = 14 This just did not work out for me. Here is my work: I first solved Equation #1 for x. x = -3y - 2z + 6 Then, I did

More Similar Questions