Find the value of y in the equation y = log 2 32.
a. 5
b.16
c.64
d. 1024
y = log2 32
then 2^y = 32
2^y = 2^5
then y = 5
To find the value of y in the equation y = log2(32), we need to evaluate the logarithm expression.
First, let's rewrite the equation using the base conversion formula:
y = log2(32) = log10(32) / log10(2)
Now, let's calculate the logarithms using a calculator:
log10(32) ≈ 1.50515
log10(2) ≈ 0.30103
Now, substitute these values back into the equation:
y ≈ 1.50515 / 0.30103 ≈ 5
Therefore, the value of y is 5.
Answer: a. 5
To find the value of y in the equation y = log2 32, we need to understand what the logarithm function represents.
In this equation, y is the exponent we need to raise the base (2) to in order to get the value of 32. Mathematically, it can be represented as y = log2(32) = x, where 2^y = 32.
To determine the value of y, we need to find the value of x that satisfies the equation 2^x = 32.
Let's start by simplifying the equation 2^x = 32. We can rewrite 32 as 2^5, as 2^5 is equal to 32. So, the equation becomes:
2^x = 2^5.
Now, we can set the exponents equal to each other, giving us:
x = 5.
Therefore, the value of y in the equation y = log2 32 is 5.
So, the correct answer is a. 5