equilibrium III

what's Kp if Cl2CO was found to be 7.46% decomposed at 395'C when initial pressure is 7.60atm.

Cl2CO --> <-- CO + Cl2

Initial p = 7.60 atm.
7.46% decomposed.
(CO) = 7.60*0.0746 = ??
(Cl2) = same
((Cl2CO) = 7.60*(0.9254) = ??

Kp = pCO*pCl2/pCl2CO
Post your work if you get stuck. Check my work. Check my thinking.

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