Two jets leave Marble Airport at 3 pm, one traveling east and the other traveling west. The westbound jet averages 625km/h and the eastbound jet averages 825 km/h.
At what time will the jets be 725 km apart?
725/(625+825) = 1/2
So, at 3:30 they will be 725km apart
To find out at what time the jets will be 725 km apart, we need to calculate the time it takes for each jet to travel a combined distance of 725 km.
Let's assume the time it takes for the westbound jet to travel this distance is 't' hours. Then the time it takes for the eastbound jet to cover the same distance would also be 't' hours.
Since the westbound jet is traveling at 625 km/hr, the distance it travels in time 't' would be 625t km. Similarly, the eastbound jet travels 825t km in time 't'.
Now, we can set up an equation to find 't':
625t + 825t = 725
Combining like terms:
1450t = 725
Dividing both sides by 1450:
t = 0.5
So, it would take 0.5 hours (or 30 minutes) for each jet to travel a combined distance of 725 km.
To determine the time they will be apart, we add this time to the departure time of 3 pm.
3:00 pm + 0.5 hours = 3:30 pm
Therefore, the jets will be 725 km apart at 3:30 pm.
To find out at what time the jets will be 725 km apart, we can use the formula Distance = Speed × Time.
Let's denote the time elapsed since 3 pm as t.
For the westbound jet, the distance traveled can be calculated as 625 km/h × t.
For the eastbound jet, the distance traveled can be calculated as 825 km/h × t.
Since the jets are traveling in opposite directions, the sum of their distances traveled will equal the total distance between them, which is 725 km.
So, we have the equation: 625t + 825t = 725.
Simplifying this equation, we get: 1450t = 725.
Dividing both sides of the equation by 1450, we find: t = 0.5.
Therefore, the jets will be 725 km apart after 0.5 hours, or 30 minutes.
Adding this time to 3 pm, we get that the jets will be 725 km apart at 3:30 pm.