physics

A bead slides without friction around a loop-the-loop. The bead is released from a
height h = 3.5R. A is at the highest point of the loop and R is the radius of the loop

(a) What is its speed at point A?

(b) How large is the normal force on it if its mass is 5g?

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  1. height at top of loop = 2 R
    so A is (3.5 - 2) = 1.5 R below drop point
    so
    (1/2) m v^2 = m g (1.5 R)
    v^2 = 3 g R

    F =m (v^2/R-g) = m (3g-g) = 2 m g
    m = .005
    g = 9.81

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  2. on a hot summer night

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