Question

For a 1.23/1 ratio of acid to base, how do you calculate the amount of a .2M base to add to 150ml of a .150M acid?

Answer 1

I may not be reading the problem right but

150 x 0.150/0.2 = 112.5 mL of 0.2 M base required. However, that isn't 1.23 ratio but 1.33; i.e., 150A/112,5B = 1,33 ratio of A/B. Did I not read the problem right or did you make a typo?