A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles.
What is the probability that you choose a red marble and then a green marble assuming you replace the first marble?
A)
1
24
B)
5
72
C)
5
66
D)
5
6
b?
12 marbles in bag, both times
5 red
2 green
5/12 * 2/12 = 10/144 = 5/72
yes B)
To find the probability of choosing a red marble and then a green marble, assuming you replace the first marble, we need to calculate two probabilities separately and then multiply them together.
First, let's calculate the probability of choosing a red marble.
Total number of marbles in the bag = 5 red + 3 blue + 2 green + 2 yellow = 12 marbles
Probability of choosing a red marble = Number of red marbles / Total number of marbles = 5/12
Since we replace the first marble, the total number of marbles in the bag remains the same for the second choice.
Next, let's calculate the probability of choosing a green marble.
Total number of marbles in the bag = 5 red + 3 blue + 2 green + 2 yellow = 12 marbles
Probability of choosing a green marble = Number of green marbles / Total number of marbles = 2/12 = 1/6
To find the probability of both events happening, we multiply the probabilities together:
Probability of choosing a red marble and then a green marble = Probability of choosing a red marble * Probability of choosing a green marble
= (5/12) * (1/6)
= 5/72
So, the correct answer is B) 5/72.