A uniform meter rule is balance at 30cm mark when of 50grams is hanging from its zero cm mark.calculate the weight of the rule?
I want the answer please
the centers of mass of the two segments of the rule are halfway from the balance point to the respective ends
let x = mass of the rule in grams
(50 g * 30 cm) + (.3 x * 15 cm) = .7x * 35 cm
after dividing by 5 ... 300 g-cm + .9x g-cm = 4.9x g-cm
solve for x
clockwise moments=anti-clockwise moments
weight1 multiplied by distance1= weight2 multiplied by distance2
50-30=20
change to newtons
0.5 multiplied by 0.3= 0.2 multiplied by distance2
=0.75 newtons