Hexane is a hydrocarbon (a molecule containing only carbon and hydrogen) with a molecular weight of 86.18 g/mol,
a density of 0.660 g/mL, and a boiling point of 69C.
Pentanol is an alcohol (a hydrocarbon with a "OH" group attached to one of its carbons) with a molecular weight of
88.15 g/mol, a density of 0.814 g/mL, and a boiling point of 137C.
Calculate the volumes if 4.50 moles of each chemical is present.
Hexane: ____mL
Pentanol: _____mL
First compute the masses using the molecular weight (which are given) and the number of moles (4.5).
Then divide by the density to get the volume.
Do this separately for each compound.
To calculate the volumes of 4.50 moles of each chemical, we can use the equation:
Volume (in mL) = Mass (in g) / Density (in g/mL)
Let's calculate the volume of hexane first:
1. Determine the mass of 4.50 moles of hexane:
Mass of hexane = Molecular weight of hexane × Moles of hexane
= 86.18 g/mol × 4.50 mol
= 387.81 g
2. Use the density of hexane to calculate the volume:
Volume of hexane = Mass of hexane / Density of hexane
= 387.81 g / 0.660 g/mL
= 588.50 mL
Therefore, the volume of hexane when 4.50 moles are present is 588.50 mL.
Now let's calculate the volume of pentanol:
1. Determine the mass of 4.50 moles of pentanol:
Mass of pentanol = Molecular weight of pentanol × Moles of pentanol
= 88.15 g/mol × 4.50 mol
= 396.68 g
2. Use the density of pentanol to calculate the volume:
Volume of pentanol = Mass of pentanol / Density of pentanol
= 396.68 g / 0.814 g/mL
= 486.92 mL
Therefore, the volume of pentanol when 4.50 moles are present is 486.92 mL.