Physics

A 0.62-mm-diameter copper wire carries a tiny current of 2.0 μA . The molar mass of copper is 63.5 g/mole and its density is 8900 kg/m3. NA=6.02×1023

Estimate the electron drift velocity. Assume one free electron per atom.

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  1. 2*10^-6 Coulombs/second pass a point on the wire every second
    1 electron is 1.6*10^-19 Coulombs
    so
    2*10^-6 Coulombs/second * 1 electron/1.6*10^-19 Coulombs
    = 1.25*10^13 electrons/second

    electrons/s = electrons/cm^3 * area*velocity =
    what is electrons/cm^3?

    density = 8900*10^3 g/10^6cm^3 = 8.9 g/cm^3
    1 electron/atom
    so 8.9 g/cm^3 * 6*10^23 electrons/mol * 1 mol/63.5 g
    = .841 * 10^23 electrons/cm^3

    so
    1.25*10^13 electrons/s = .841*10^23 electrons/cm^3 * pi d^2/4 * V

    v is in cm/s of course, divide by 100 for m/s

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