What is the total molar concentration of all the ions in 0.0200 M solutions of the following salts in water?
0.0200 M KCl
0.0200 M CuSO4
0.0200 M CaCl2
0.0200 M KCl = 0.0400M (0.0200 M of K + 0.0200 M of Cl = 0.0400M KCl)
0.0200 M CuSO4 = 0.0400M (0.0200 M of Cu + 0.0200 M SO4 = 0.0400M CuSO4)
0.0200 M CaCl2 = 0.0600 M (0.0200 M of Ca + 0.0400 M of Cl = 0.0600 M of CaCl2)
Well, these salts really know how to make a splash in water! Let's calculate the total molar concentration of ions for each of them one by one:
For 0.0200 M KCl, when this salt dissolves in water, it will dissociate into K+ and Cl- ions. Since there is only one K+ ion and one Cl- ion per molecule of KCl, the total number of ions will be double the concentration of the salt. Therefore, the total molar concentration of ions in this solution will be 0.0400 M.
Next up is 0.0200 M CuSO4. When this salt dissolves, it breaks down into Cu2+ and SO4^2- ions. Similar to before, the total molar concentration of ions will be double the concentration of the salt. So, the total molar concentration of ions in this solution will also be 0.0400 M.
Lastly, we have 0.0200 M CaCl2. When this salt dissolves, it dissociates into Ca2+ and Cl- ions. Since there are two Cl- ions per molecule of CaCl2, the total molar concentration of ions will be triple the concentration of the salt. Therefore, the total molar concentration of ions in this solution will be 0.0600 M.
So, in conclusion:
- For 0.0200 M KCl: The total molar concentration of ions is 0.0400 M.
- For 0.0200 M CuSO4: The total molar concentration of ions is also 0.0400 M.
- For 0.0200 M CaCl2: The total molar concentration of ions is 0.0600 M.
Hope that clears things up in a fun way!
To determine the total molar concentration of all ions in a solution, you need to consider the dissociation of the salt into its constituent ions.
1. 0.0200 M KCl:
Since KCl is a strong electrolyte, it fully dissociates into K+ and Cl- ions in water. Therefore, the concentration of each ion is equal to the initial concentration of the salt:
K+: 0.0200 M
Cl-: 0.0200 M
2. 0.0200 M CuSO4:
CuSO4 dissociates into Cu2+ and SO4^2- ions in water. Similarly, the concentration of each ion is equal to the initial concentration of the salt:
Cu2+: 0.0200 M
SO4^2-: 0.0200 M
3. 0.0200 M CaCl2:
CaCl2 dissociates into Ca2+ and two Cl- ions in water. However, since there are two Cl- ions for every Ca2+ ion, the concentration of Ca2+ will be half of the initial concentration of the salt, while the concentration of Cl- will be double:
Ca2+: 0.0200 M / 2 = 0.0100 M
Cl-: 2 * 0.0200 M = 0.0400 M
So, the total molar concentration of all ions in the given salts is as follows:
For KCl:
K+: 0.0200 M
Cl-: 0.0200 M
For CuSO4:
Cu2+: 0.0200 M
SO4^2-: 0.0200 M
For CaCl2:
Ca2+: 0.0100 M
Cl-: 0.0400 M
To find the total molar concentration of ions in a solution, we need to consider the dissociation of the salt into its constituent ions. The concentration of each ion is determined by multiplying the concentration of the salt by the number of ions that it dissociates into.
For KCl, it is a 1:1 electrolyte, meaning that it dissociates into one potassium ion (K+) and one chloride ion (Cl-). Therefore, the molar concentration of each ion is the same as the molar concentration of the salt, which is 0.0200 M.
For CuSO4, it is a 1:1 electrolyte as well, meaning that it dissociates into one copper ion (Cu2+) and one sulfate ion (SO4 2-). Again, the molar concentration of each ion is the same as the molar concentration of the salt, which is 0.0200 M.
Lastly, for CaCl2, it is a 1:2 electrolyte, meaning that it dissociates into one calcium ion (Ca2+) and two chloride ions (Cl-). To calculate the molar concentration of each ion, we multiply the molar concentration of the salt (0.0200 M) by the number of ions formed. So, the concentration of Ca2+ will be 0.0200 M, and the concentration of Cl- will be 2 * 0.0200 M = 0.0400 M.
Therefore, the molar concentration of all the ions in each solution is as follows:
KCl: 0.0200 M K+ and 0.0200 M Cl-
CuSO4: 0.0200 M Cu2+ and 0.0200 M SO4 2-
CaCl2: 0.0200 M Ca2+ and 0.0400 M Cl-
0.0200 M CaCl2.
So you have 0.0200 M Ca^2+ and 2*0.0200 M Cl^- and the total is 0.0200 + 0.0400 = 0.0600 M total.
You do the other two the same way. Post your work if you get stuck.