Xe+3F_2=XeF_6
How many mol of xenon hexafluoride are produced from 4.01 x 102 mol of fluorine (F2)?
See your other post of O3 and O2 to see how to set it up. You can see that you ca convert mols of anything to mols of anyy other thing in the equation by using the coefficients.
To find out how many moles of xenon hexafluoride (XeF6) are produced from a given amount of fluorine (F2), we need to use the balanced chemical equation for the reaction:
Xe + 3F2 → XeF6
According to the equation, we can see that 3 moles of fluorine (F2) react with 1 mole of xenon (Xe) to produce 1 mole of xenon hexafluoride (XeF6).
Given that you have 4.01 x 10^2 moles of fluorine (F2), we can set up a proportion to find the number of moles of xenon hexafluoride (XeF6):
(4.01 x 10^2 mol F2) / (3 mol F2) = (x mol XeF6) / (1 mol XeF6)
Using cross-multiplication, we can solve for x:
x mol XeF6 = (4.01 x 10^2 mol F2) / (3 mol F2)
x = (4.01 x 10^2 mol F2) / (3 mol F2)
Calculating this expression will give you the number of moles of xenon hexafluoride (XeF6) produced from the given amount of fluorine (F2).