How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.26 L against a constant pressure of 0.857 atm?
work = -p(v2-v1)
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To determine the work involved in a chemical reaction, we can use the formula:
Work = -PΔV
where P is the pressure and ΔV is the change in volume.
Given:
Initial volume (V₁) = 5.00 L
Final volume (V₂) = 1.26 L
Pressure (P) = 0.857 atm
First, let's calculate the change in volume:
ΔV = V₂ - V₁
ΔV = 1.26 L - 5.00 L
ΔV = -3.74 L
Note that the change in volume is negative because the volume is decreasing.
Now, we can calculate the work using the formula:
Work = -PΔV
Work = -(0.857 atm)(-3.74 L)
Calculating the work:
Work = 3.20 atm·L
Since 1 atm·L = 101.3 J, we can convert the units:
Work = 3.20 atm·L × 101.3 J/atm·L
Work ≈ 324.56 J
Therefore, the work involved in the chemical reaction is approximately 324.56 J.
To calculate the work involved in a chemical reaction, we can use the formula:
Work (W) = -PΔV
Where:
W = work done (in joules)
P = pressure (in atmospheres)
ΔV = change in volume (in liters)
In this case, the volume decreases from 5.00 L to 1.26 L. Thus, the change in volume (ΔV) will be:
ΔV = final volume - initial volume
= 1.26 L - 5.00 L
= -3.74 L
Note that the negative sign signifies a decrease in volume.
Given that the pressure (P) is constant at 0.857 atm, we can substitute these values into our formula:
W = -PΔV
= -(0.857 atm)(-3.74 L)
Multiplying these values gives:
W = 3.20218 atm L
However, to express the work in joules, we need to convert from atm L to joules. To do this, we'll use the conversion factor:
1 atm L = 101.3 J
So, multiplying the work in atm L by the conversion factor gives:
W = (3.20218 atm L)(101.3 J / 1 atm L)
= 324.53 J
Therefore, the work involved in the chemical reaction is approximately 324.53 J.