Physics

A thread of mercury of length 15cm is used to trap some air in a capillary tube with uniform cross sectional area and closed at one end.With the tube vertical and the open end uppermost,the length of the trapped air column is 20cm.calculate the length of the air column when the tube is held(!)horizontally (!!)vertically with the open end underneath.atmospheric pressure =76cm of mercury

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  1. at the start air pressure in bottom of tube = 76 + 15 = 91 cm Hg
    when horizontal the pressure will be 76+0 = 76 cm
    P2 V2 = P1 V1 since n and R and T are the same

    20 * 91/76 = 23.9

    when upside down
    Pair = 76 - 15 = 61 cm Hg
    20 * 91/61 = 29.8

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  2. What if an atmospheric pressure is not given

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