physics

A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 14 m/s. If the brick is in flight for 3s, how tall is the building?

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asked by TNT
  1. I told you how to do this type of problem earlier.

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    posted by Damon
  2. Vo = 14m/s[35o].
    Yo = 14*sin35 = 8.03 m/s.

    Y = Yo + g*Tr = 0 at max ht.
    8.03 - 9.8Tr = 0,
    Tr = 0.82 s. = Rise time.

    Tf = Tr = 0.82 s. = Time to fall back to top of bldg.

    T = 3-(0.82+0.82) = 1.36 s. = Time to fall from top of bldg. to gnd.

    h = Vo*T + 0.5g*T^2.
    Vo = 14 m/s, T = 1.36 s, g = + 9.8 m/s^2, h = ?.

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    posted by Henry

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