How many moles of H2SO4 are present in 250 g of an aqueous solution that is 4.8 m (molal)? The density of the solution is1.58 g/mL.
m = mols/kg solution.
So a 4.8 m soln is 4.8 mol/kg soln.
If you have 4.8 mols in 1 kg how much do you have in 250 g? Wouldn't that just be 4.8 mols x (250 g/1000 g) = ? = say 4.8/4 = 1.2 molsposted by DrBob222