Chemistry

How many moles of H2SO4 are present in 250 g of an aqueous solution that is 4.8 m (molal)? The density of the solution is1.58 g/mL.

asked by TP
  1. m = mols/kg solution.
    So a 4.8 m soln is 4.8 mol/kg soln.
    If you have 4.8 mols in 1 kg how much do you have in 250 g? Wouldn't that just be 4.8 mols x (250 g/1000 g) = ? = say 4.8/4 = 1.2 mols

    posted by DrBob222

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