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Two charged particles are 8.5cm apart .They moved and the force on each of them is found to be tripled .How far apart are they now

asked by samuel
  1. F = constant / d^2
    3 F = constant /x^2

    F = c/(8.5^2)
    3 F = 3c/(8.5^2) = c/x^2
    3 x^2 = 8.5^2
    x = 8.5/sqrt(3)

    posted by Damon
  2. electric field strength follows the inverse square law

    f d^2 = (3f) D^2

    D^2 = d^2 / 3

    D = 8.5 / √3

    posted by Scott

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