physics
Rewrite the following vectors in terms of their magnitude and angle (counterclockwise from the +x direction).
1) A displacement vector with an x component of +9.5 m and a y component of 9.6 m.
magnitude:
2) angle:
3) A velocity vector with an x component of 96 m/s and a y component of +46 m/s.
magnitude:
4) angle:
5) A force vector with a magnitude of 58 lb that is in the third quadrant with an x component whose magnitude is 37 lb.
y component:
6) angle:

1. Disp. = X  yi = 9.5  9.6i =
Sqrt(9.5^2+9.6^2) =
2. Tan A = (9.6/9.5 = 1.01053.
A = 45.3o,Q4 = 45o S. of E. = 315o CCW.
3. V = 96 + 46i = Sqrt(96^2+46^2) =
4. Tan A = 46/(96) = 0.47917.
A = 25.6o, Q2 = 25.6o N. of W. = 154.4o CCW.posted by Henry

5. X^2 + Y^2 = 58^2.
37^2 + Y^2 = 58^2. Y = ?.
6. Q3, 37  Yi.
Calculate the angle.
posted by Henry
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