Calculate the linear expansivity of a brass of length 120m that assume a new length of 120.05m when heated through a temperature of 100°c
linear expansivity =L2-L1/L1<tita>
linear expansivity=120.05-120 / 120<100>
linear expansivity=0.05 / 12,000
linear expansivity=0.000417
Review your text.
Expansivity is expressed in m/° = ∆L/∆T, so what do you think?