find g(x+3) given g(x)=5x-1
g(x) = 5x - 1
Let's take y = x + 3
Now, g(y) = 5y - 1
So, g(x + 3) = 5y - 1
But y = (x + 3)
=> g(x + 3) = 5(x + 3) - 1
= 5x + 15 - 1
= 5x + 14
Given: g(x) = 5x-1.
Find: g(x+3).
In the given Eq, replace x with (x+3):
g(x+3) = 5(x+3) - 1.
g(x+3) = 5x + 14.
To find g(x+3) using the given function g(x) = 5x - 1, we substitute (x+3) into the function in place of x.
So, g(x+3) = 5(x+3) - 1
To simplify it further, we distribute the 5 to (x+3):
g(x+3) = 5x + (5*3) - 1
g(x+3) = 5x + 15 - 1
Finally, we combine the like terms:
g(x+3) = 5x + 14
Therefore, g(x+3) = 5x + 14.