WHAT PRESSURE WILL BE COMPRESS 7.75 LITRES OF HYDROGEN AT ATMOSPHERIC PRESSURE TO 5 LITRES?
At constant T, p1v1 = p2v2
It will be 1.55atmospheric pressure
please help me
To calculate the pressure when compressing a gas, we can use Boyle's Law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume. In mathematical terms:
P1 * V1 = P2 * V2
Given that:
V1 (initial volume) = 7.75 liters
P1 (initial pressure) = atmospheric pressure (let's convert it to the appropriate unit shortly)
V2 (final volume) = 5 liters
First, let's convert atmospheric pressure to the appropriate unit, which is usually measured in Pascals (Pa) or kilopascals (kPa). The most common unit used to express atmospheric pressure is in millimeters of mercury (mmHg) or torr. 1 atm is approximately equal to 760 mmHg or 760 torr.
Let's assume the atmospheric pressure is 1 atm, then we have:
P1 = 1 atm (which is equal to 760 mmHg or 760 torr)
Now, we can rearrange the formula and solve for P2:
P2 = (P1 * V1) / V2
P2 = (1 atm * 7.75 liters) / 5 liters
P2 = 7.75/5 atm
Finally, we can calculate P2:
P2 = 1.55 atm
Therefore, when compressing 7.75 liters of hydrogen at atmospheric pressure to 5 liters, the pressure will increase to approximately 1.55 atm.