# Math

Suppose A,B, and C are positive integers such that 24/5 = A + 1/B+1/C+1

The value of 1A + 2B + 3C equals:

(A) 9 (B) 12 (C) 15
(D) 17 (E) 20

hey i am trying to solve the problem, is it written like
A+1
_____
B+1/C+1

A + 1
______
B + 1
____
C + 1

sorry it sort of doesnt make sense i am really good at math too... so it is written like
a+1
________
B+1
__
C+1

from your equation we can say

A + 1/B + 1/C = 19/5 (subtract 1 from both sides)

since the common denominator BC is 5
B=1 and C=5 or B=5 and C=1

neither combination produces your stated result,
but when A=3, B=-5 and C=1

we get 3 -1/5 + 1 = 19/5

we get the same result when A=3, B=1 and C=-5

I actually ran a computer program in QuickBasic which gave me the following results, which all work in your original equation

A,B,C
4,-5,1
4,1,-5
5,-30,-6
5,-10,-10
6,-1,-5

THERE IS NO SOLUTION FOR ALL POSITIVE INTEGERS

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