How many odd three -digit numbers can be formed if the tens digit must be 4 ?(Repetition of digits is allowed and zero cannot be the hundreds’ digit)
9 choices for hundreds , and 5 choices for ones
9 * 5 = ?
Why is there 9 choices for hundreds
there are ten digits , but zero is not allowed
To find the number of odd three-digit numbers that can be formed with the tens digit as 4, we need to consider the possible values for the hundreds and units digits.
Since zero cannot be the hundreds' digit, the possible values for the hundreds digit are 1, 2, 3, 5, 6, 7, 8, and 9 (8 options).
For the units digit, odd numbers are 1, 3, 5, 7, and 9 (5 options).
Since repetition of digits is allowed, each digit can be chosen independently.
Therefore, the total number of odd three-digit numbers that can be formed is obtained by multiplying the number of options for each digit: 8 (options for digit hundreds) * 1 (option for digit tens, fixed as 4) * 5 (options for digit units).
Thus, the total number of odd three-digit numbers that can be formed with the tens digit as 4 is 8 * 1 * 5 = 40.