The sum of two consecutive numbers is n+1. What are the numbers?
let the first be x
then the next is x+1
x + x+1 = n+1
2x = n
x = n/2
the numbers are n/2 and n/2+1 or (n+2)/2 , where n is an even number.
e.g. let n = 6
then x = 3, and (n+2)/2 = 4
their sum is 7 OR n+1 which is also 7
So bad
Well, let's call the first number x. So, the next consecutive number would be x+1.
According to the question, the sum of these two numbers is n+1. So, we can write an equation:
x + (x+1) = n+1
Simplifying, we get:
2x + 1 = n+1
Now, if we subtract 1 from both sides:
2x = n
Dividing both sides by 2 gives us:
x = n/2
So, one of the consecutive numbers is n/2, and the other one is n/2 + 1.
But you know what they say, nothing is more awkward than a half of a number trying to fit in as a consecutive number. It's like trying to squeeze a square peg into a round hole. So, let's just move on and find a more suitable problem, shall we?
Let's solve this step-by-step.
Let's assume the first number is x.
According to the problem, the next consecutive number would be x + 1.
Given that the sum of these two consecutive numbers is n + 1, we can write the equation as:
x + (x + 1) = n + 1
Simplifying the equation:
2x + 1 = n + 1
Subtracting 1 from both sides:
2x = n
Dividing both sides by 2:
x = n/2
So, the first number is n/2, and the next consecutive number is (n/2) + 1.
To find the consecutive numbers, we need to set up an equation based on the information given. Let's assume the first number is x.
The next consecutive number is then x + 1, since they are consecutive.
According to the information given, the sum of the two numbers is n + 1. So, we can set up the equation:
x + (x + 1) = n + 1
Simplifying the equation, we combine like terms:
2x + 1 = n + 1
Now, we isolate x by subtracting 1 from both sides of the equation:
2x = n
Finally, we divide both sides of the equation by 2 to solve for x:
x = n/2
Therefore, the first number is n/2, and the second consecutive number is (n/2) + 1.