5.30g of pure anhydrous sodium carbonate, na2co3 was weighed and dissolved in a 250cm³ standard flask.The solution was made up to the etched mark with distilled water, calculate the number of moles of na2co3 in the solution.
Number of moles = Mass of substance / Molecular Mass
Molecular Mass = 106 g
Mass of substance = 5.3 g
=> Number of moles = 5.3/106
= 1/20
= 0.05
To calculate the number of moles of Na2CO3 in the solution, we need to use the formula:
moles = mass / molar mass
1. Determine the molar mass of Na2CO3:
The molar mass of sodium (Na) is 22.99 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol.
Na2CO3 consists of 2 sodium atoms, 1 carbon atom, and 3 oxygen atoms.
Molar mass of Na2CO3 = (2 * Na) + C + (3 * O)
= (2 * 22.99) + 12.01 + (3 * 16.00)
= 45.98 + 12.01 + 48.00
= 105.99 g/mol
2. Calculate the number of moles of Na2CO3:
moles = mass / molar mass
moles = 5.30 g / 105.99 g/mol
moles ≈ 0.05 mol
Therefore, there are approximately 0.05 moles of Na2CO3 in the solution.
To calculate the number of moles of Na2CO3 in the solution, you need to use the formula:
Moles = Mass / Molar mass
First, let's find the molar mass of Na2CO3.
Molar mass of Na2CO3 = (2 * Molar mass of Na) + Molar mass of C + (3 * Molar mass of O)
From the periodic table, we can find the molar masses:
Molar mass of Na = 22.99 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Substituting these values into the equation, we get:
Molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00)
Molar mass of Na2CO3 = 45.98 + 12.01 + 48.00
Molar mass of Na2CO3 = 105.99 g/mol
Now, we can calculate the number of moles:
Moles = Mass / Molar mass
Moles = 5.30 g / 105.99 g/mol
Moles = 0.0499 mol
Therefore, the number of moles of Na2CO3 in the solution is approximately 0.0499 mol.