In an experiment to find the speed of 2.4g bullet, it was fired into a 650g block of wood at rest on a friction free surface. If the block(and bullet) moved off with an initial speed of 96cm s-1, what was the speed of the bullet?
plz help the teacher gave us homework without explaining how to do it
in kg, meters, seconds:
bullet mass = 0.0024 kg
0.0024 v = (0.650 + 0.0024)(0.96)
v will be in METERS/second
Given:
M1 = 0.0024kg, V1 = ?.
M2 = 0.650kg, V2 = 0.
V3 = 0.96 m/s = Velocity of M1 and M2 after the c024V1ollision.
Momentum before = Momentum after:
M1*V1 + M2*V2 = M1*V3 + M2*V3,
0.0024*V1 + 0.65*0 = 0.0024*0.96 + 0.65*0.96,
V1 = ?.
V3 = 0.96 m/s = Velocity of M1 and M2 after the collision.
To find the speed of the bullet, we can use the concept of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event in the absence of external forces.
In this scenario, the total momentum before the bullet hits the block is zero since the block is initially at rest. After the bullet hits the block, both the block and the bullet move off together.
To start solving the problem, we need to determine the momentum of the block and the bullet after they start moving. The momentum of an object can be calculated by multiplying its mass by its velocity.
Given:
Mass of the bullet (m1) = 2.4g = 0.0024 kg
Mass of the block (m2) = 650g = 0.65 kg
Initial speed of the block and bullet (v) = 96 cm/s = 0.96 m/s
Let the velocity of the bullet after the collision be v1.
Let the velocity of the block after the collision be v2.
According to the law of conservation of momentum:
m1*v = (m1 + m2)*(v1 + v2)
Substituting the given values:
0.0024 kg * 0.96 m/s = (0.0024 kg + 0.65 kg) * (v1 + v2)
Simplifying the equation:
0.002304 kg*m/s = 0.6524 kg * (v1 + v2)
Now, we can rearrange the equation to solve for v1, the speed of the bullet:
v1 = (0.002304 kg*m/s) / 0.6524 kg - v2
Remember that the initial speed of the block and bullet is 0.96 m/s. Therefore, we can substitute the value of v2 into the equation to find v1:
v1 = (0.002304 kg*m/s) / 0.6524 kg - 0.96 m/s
Using a calculator, we can evaluate the equation to find the value of v1. This will give us the speed of the bullet after the collision with the block.
I hope this explanation helps you understand the process of solving this problem.