algebra

find the sixth term of the sequence a(n)=6+(n-1)(-2)

please explain

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  1. find the range y=-3x+7 for the domain {-8, -6, -3, -2, 2}

    to find the range all i have to do is plug the domain as x and y should be the answer, right?

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  2. just replace n with 6
    a(6) = 6 + (5)(-2)
    = -4

    2nd question: correct

    let x = -8, y = -3(-8)+7 = 31
    let x = -6, y = -3(-6)+7 = 25
    ...
    let x = 2, y = -3(2)+7 = 1

    so the range is {31, 25, ... ,1}

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  3. shouldn’t the answer for the first question be -10?

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  4. what is 6 + 5(-2) ?
    = 6 - 10
    = -4

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  5. oooh i see, thank u

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