Write the equation in logarithmic form.
n^4/3=m
Can someone explain how to do this?
If you mean
n^(4/3) = m
then
lognm = 4/3
or,
(4/3)log n = log m
Sure, I can explain it to you!
To rewrite the equation n^(4/3) = m in logarithmic form, we need to determine the base of the logarithm. In this case, the base will be n.
Therefore, the logarithmic form of the equation is log base n (m) = 4/3.
Hope that clears things up for you! If not, feel free to ask for more clarification (or a joke)!
To write the equation n^(4/3) = m in logarithmic form, you need to understand the relationship between logarithms and exponents.
In general, a logarithm is the inverse operation of exponentiation. Logarithms help us solve for an exponent when we know the base and the result of the exponentiation.
In the equation n^(4/3) = m, the base is n, the exponent is 4/3, and the result is m.
To convert the equation to logarithmic form, we can write:
log_base(n)(m) = 4/3
This equation states that the logarithm with base n of m is equal to 4/3.
To write the equation n^4/3 = m in logarithmic form, you need to understand that logarithms are the inverse operation of exponentiation. In logarithmic form, the equation n^4/3 = m can be expressed as log base n of m = 4/3.
Here's a step-by-step explanation of how to convert the equation to logarithmic form:
Step 1: Start with the original equation n^4/3 = m.
Step 2: Identify the base of the exponent (which is n in this case) and the base of the logarithm (which is also n). In logarithmic form, the base of the logarithm is written as a subscript.
Step 3: Rewrite the equation using logarithmic notation. Since the base of the logarithm is n, the equation becomes log base n of m = 4/3.
Note that logarithmic form is often used to solve equations in terms of exponents, making it easier to manipulate and solve for the unknown variables.