x^2 = x^2-1 = x^2-1 = (x-1)(x+1) -x = 1
x-1 x-1
Is this right, please help me solve
To check if the equation is correct, we need to simplify it and see if both sides are equal.
Starting with the left side:
x^2
And now let's simplify the right side:
(x-1)(x+1) - x = (x^2 - 1) - x = x^2 - 1 - x = x^2 - x - 1
Now we have:
x^2 = x^2 - x - 1
From here, we can see that the equation is not correct because we have different terms on both sides of the equation.
To solve an equation, we want to isolate the variable on one side. Let's correct the equation and solve for x:
x^2 - x - 1 = 0
Now, we have a quadratic equation. We can use the quadratic formula to solve for x:
x = (-b ± √(b² - 4ac)) / (2a)
For our equation, a = 1, b = -1, and c = -1:
x = (-(-1) ± √((-1)² - 4(1)(-1))) / (2(1))
x = (1 ± √(1 + 4)) / 2
x = (1 ± √5) / 2
So the solutions to the equation are x = (1 + √5) / 2 and x = (1 - √5) / 2.