Pre-Calculus 12

Solve using logarithm:
2^(4x+1)=3^x

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  2. 7
asked by Rayan
  1. take logs of both sides

    log 2^(4x+1) = log 3^x
    use rules of logs
    (4x+1)log2 = xlog3
    4xlog2 + log2 = xlog3
    4xlog2 - xlog3 = -log2
    x(4log2 - log3) = -log2
    x = -log2/(4log2 - log3)
    x = log2/(log3 - 4log2)
    = ..

    let the button-pushing begin

    posted by Reiny
  2. Thank you!

    posted by Rayan

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