Pre-Calculus 12

Solve using logarithm:
2^(4x+1)=3^x

1. 0
2. 7
1. take logs of both sides

log 2^(4x+1) = log 3^x
use rules of logs
(4x+1)log2 = xlog3
4xlog2 + log2 = xlog3
4xlog2 - xlog3 = -log2
x(4log2 - log3) = -log2
x = -log2/(4log2 - log3)
x = log2/(log3 - 4log2)
= ..

let the button-pushing begin

posted by Reiny
2. Thank you!

posted by Rayan

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