Physics

What force is required to stop a 1500-kg car in a distance of 0.20 m if it is initially moving at 2.2 m/s?

  1. 7
asked by Will
  1. Friction...

    posted by Anonymous
  2. work done by force = F d = 0.20 d Joules
    kinetic energy = (1/2) m v^2
    work done to stop = kinetic energy
    0.20 d = (1/2)(1500)(2.2)^2

    posted by Damon
  3. V^2 = Vo^2 + 2a*d.
    0 = (2.2)^2 + 0.4a,
    a = -12.1 m/s^2.

    F = M*a = 1500*(-12.1) = -18,150 Joules.

    The negative sign means the force opposes the motion.

    posted by Henry

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