Chemistry

What is the ionization constant for a weak acid HA that is 1.60% ionized in 0.095M solution?

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asked by Zekariyas
  1. ........HA ==> H^+ + A^-
    I......0.095...0.....0

    So (H^+) = (A^-) = 0.095*0.016

    Substitute into Ka expression and solve for Ka.

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    posted by DrBob222

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