2) Find the expression for the solubility product of silver oxalate Ag2C2O4).
The solubility of Ag2NtO4, silver nortonate, in pure water is 4.0 x 10-5 moles per liter. Calculate the value of Ksp for silver nortonate.
I have been in this business a LONG time and I've never heard of silver nortonate. Tell me something abouat it. Nor do I know the identity of Ag2NtO4
To find the expression for the solubility product of silver oxalate (Ag2C2O4), we need to write its chemical equation and then determine the equilibrium expression.
The chemical equation for the dissociation of silver oxalate is as follows:
Ag2C2O4(s) ⇌ 2Ag+(aq) + C2O42-(aq)
The solubility product expression represents the equilibrium constant of the dissolution process. In this case, it is represented as:
Ksp = [Ag+]^2 * [C2O42-]
Where [Ag+] represents the concentration of silver ions in the solution, and [C2O42-] represents the concentration of oxalate ions.
Note that the concentration of a solid (Ag2C2O4) does not appear in the expression, as its value remains constant and is incorporated into the equilibrium constant.
So, the expression for the solubility product of silver oxalate (Ag2C2O4) is:
Ksp = [Ag+]^2 * [C2O42-]