Calculus

A piece of wire 7 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle.
A. How much wire should be used for the square in order to maximize the total area?
B. How much wire should be used for the square in order to minimize the total area?

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asked by Anon
  1. let x = side of triangle
    let s = side of square
    then
    7 = 3 x + 4 s so s = (1/4)[7-3x]
    A = (1/4)x^2sqrt 3 + s^2
    A = (1/4)x^2 sqrt 3 +(1/16)[49-42x+9x^2]
    dA/dx= (x/2)sqrt 3 +(1/16)[18x-42]
    set to zero for max and min value of x
    for which is max
    d^2A/dx^2 = (1/2)sqrt3 + (9/8)x
    if positive, min
    if negative, max

    Remember x is the triangle side, s = (1/4)(7-3x)

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    posted by Damon

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