chemistry

19.4 g of butane (58.12 g/mol) undergoes combustion according to the following equation. What pressure of carbon dioxide in atm is produced at 309 K in a 1.15 L flask.

2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)

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asked by milo
  1. Balance the equation.
    Convert g butane to mols.
    Using the coefficients in the balanced equation, convert mols butane to mols CO2.
    Use PV = nRT substitute and solve for P of CO2

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    posted by DrBob222

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