physics

At a playground, a 19.7-kg child plays on a slide that drops through a height of 2.29 m. The child starts at rest at the top of the slide. On the way down, the slide does a nonconservative work of -368 J on the child. What is the child's speed at the bottom of the slide?

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  1. (1/2) (19.7) v^2 = (19.7)(9.81)(2.29)-368

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    posted by Damon

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