algebra

A man can do a certain task in 21 hours, another man can do the task in 28 hours and a boy can do the task in 48 hours. Find how long it will take to do the task if all three work.

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  1. You've already posted the exact same question, to which I replied.

    You also posted an earlier, similar question, which was answered. Did you not learn from the process on the other question?

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  2. they each do a fraction of the task, based on their individual times ... the fractions sum to one (the whole task)

    t/21 + t/28 + t/48 = 1 ... LCD is ... 21 * 16

    16t/336 + 12t/336 + 7t/336 = 336/336

    35t = 336

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  3. noted

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