Math

The sum of the digits of a three digit number is 20.The middle digit is equal to one fourth the sum of the other two. If the order of the digits is reversed the number increases by 198. Find original number

1. If the digits are xyz, then we are told

x+y+z = 20
y = (x+z)/4
100z+10y+x = 198 + 100x+10y+z

Now just solve for x,y,z

posted by Steve

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