# PreCalc

When the polynomial p(x) is divided by (x–2), the remainder is 3 and when p(x) is divided by (x+1) the remainder is 9. Given that p(x) may be written in the form (x–2)(x+1)q(x) + Ax + B where q(x) is a polynomial and A and B are numbers, find the remainder when p(x) is divided by (x–2)(x+1).

1. 4
asked by Anthony
1. Can someone please actually help?

posted by Anthony
2. impatient much? We don't all just sit by our computers all day waiting for postings. We also have lives.

we are given
p(2) = 3
p(-1) = 9

so, using those values (and recognizing that the (x–2)(x+1)q(x) part is zero),

2A+B = 3
-A+B = 9

solve for A and B, and Ax+B is the remainder.

posted by Steve
3. Steve,

My apologies but the only reason I said that was because some random person kept spamming this question with random sayings and it kinda got annoying. I didn't mean to offend you in any way

posted by Anthony
4. yeah, that happens some here.

posted by Steve

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